CoolCat
Well-known member
heres one with No leakage...go figure?
This makes sense, thanks. good explanation imo.Yeah, the key thing to get is that in proper working condition, banks 1+2 do not light up at the same time.
It just looks like they do, because they alternate fast.
If I sped up my simulation to a few hundred hz, it would just look like both meters were lit a the same time.
With that knowledge you can work out that Q101 is the switch that turns on and off channel 1.
and it also also turns on and off Q102.
When one is open the other is closed, and vice versa.
LEDMux is the trigger which rapidly switches to control the whole thing.
By design, when LEDMux is 0V, Q101 passes which
1: Lights up channel 1
2: Lifts Q102 base, closing it, and turning off channel 2
then when LEDMux is 5V, Q101 shuts which
1: Kills channel 1 LEDs
2: Lowers Q102 base (by cutting off 5v to it) which lights up channel 2.
Knowing that ^^ you know there should only ever be 5V available at Q101 collector (for LEDS CH1) or Q102 collector (for LEDS CH2),
but never both.
Not quite...I'm describing how the circuit works properly...Not the failure.0v...Q1 passes to turn on LED
5v...Q1 closed and turns off LED...because its tied to Q2 this opposite effect opens Q2 a little bit and weak LED are ON.
happening really fast so , yeah, good refresh on basic Transistor workings.
I haven’t read the whole thread so forgive this intrusion : Is the leakage on the LEDs or it is also in the Audio between Channels?Would reducing the 5V weaken the circuit enough to not show enough leakage to turn on the unused channel?
so AI is wrong saying the chips are interchangeable.