Hello alecmcmahon, say, didn't mean to give you a hard time. Sometimes I come off that way. Ok, what you have is the equivilent of a sheet and a half of 4x8 ply. Personally, I would use 4 pieces, diagonally ACROSS the wall intersections(corners) at each end of your console, 12" from the ceiling on down or from the console height uppward. To do this, nail a 1x1 wood cleat vertically on each wall, so that it measures 1/4" smaller between the cleats diagonally across the corner, than the tile face dimension. Just force the tiles in between these cleats or glue them along the vertical edge. Thats 8 pieces total. That leaves 40 squares. I'd use 8, in each of the rear corners, floor to ceiling. That leaves 24. Then I'd sit at the engineering position, and have someone hold a mirror about the same size as the foam tiles, and hold it against ONE side wall, and move it around till you see a monitor in the mirror from the engineering position. Think of that as the CENTER of a soundwave EARLY REFLECTION, and the intersection of 4 tiles forming a square. Then do the same on the opposite side wall. Now, I would use another 4 tiles in a square, or 6 tiles in a rectangle, on the ceiling right above but a little forward of the engineering position. Use the mirror if you can. Then use the balance of the tiles on the rear wall behind the engineering position, in a checkerboard pattern, two rows high, centered on the wall, the horizontal line between two tiles at ear height. This will provide some diffusion at the rear wall, as well as more absorption than the tiles placed side by side, as there is a phenomena called the "edge effect", which states more or less, that ........."the total absorption of a given square footage of absorbant material is increased if this square footage is divided into patches, where each patch has a reflective boundary along each of its edges"....?Don't ask me why. All I know is that it exists, as tests have confirmed it

ALSO, the edges of absorbant material contribute to overall absorption, and anyone who places 2" to 4" fiberglass panels in wood frames looses a LOT of absorption, as the perimeter length of a 2'x4' panel times the thickness equals a LOT of area that contributes to the overall absorption. Hmmmmmmm, does that make sense?

On ONE 2" thick panel, thats a whopping 288 square inchs, or 2 full square feet of absorption area!!! On ONE panel

So, you can see that multiple panels can loose a lot of area by covering the edges. Not only that, but the absorption is at 90 degrees to the face, so incident angle absorption increases too, if there is a reflective boundary next to it or not.
BTW, you will also lower the bandwidth of your tiles, if you glue a piece of 1" square foam or wood "standoff"at least a half inch thick on each corner of each of the tiles used parallel to the wall and ceiling. This gives an airgap behind them, which technically is just increasing the "thickness" of the tiles, but also, reducing the "waste" of the tile thickness as velocity of molecule movement at a boundary(the wall behind the tiles) is ZERO. Well, hope this helps, and again, this stuff is mostly covered by my disclaimer, and subject to abuse by the user or other replys by experts.
fitZ
PS, since your console is so close to the wall and speakers, you MAY not see the monitors in a mirror. In that case, use these tiles right up next to the front corner tiles, vertically. Well, thats my .02 anyway.