EQ "Q" values explained?

  • Thread starter Thread starter businessnotplea
  • Start date Start date
B

businessnotplea

New member
Hi, I do understand that the Q control on a EQ increases/decreases the bandwidth of frequencys, often you will hear I used a "Low Q setting" or a Q of 2. I was just wondering do the actual numbers of the Q settings actually mean anything to anybody? Does a certain number have differnt jobs apart from "Cut narrow boost wide"? I feel like I'm missing something. Is the answer simply use your ear? Also any starting points such as a Q of 3 for this is good, a 5 that that would be appreciated. Thank you.
 
Q has always been weird to figure out for me. The smaller the number, the wider the Q and vice versa. I once read and figured out the formula for Q settings. It had something to do with subtracting the lower frequency from the the higher frequency or something. Something along the lines of: If I'm cutting at 400hz, a Q of 2 means that the range goes from 300hz to 500hz, since 500-300=200hz, which is half of 400hz. So, 2 represents 1/2, 4 represents a 1/4.....or something like that.

*DON'T QUOTE ME ON THE ABOVE FORMULA. I'M SURE IT'S WRONG. Hopefully someone that actually knows what they're talking about will know what I'm trying to get at and correct it.

As far as Q values that go from 1 to 100, I have no idea other than 1 is really wide and 100 is like a notch filter.
 
This is exactly what I meant.


:D :D :D

Physically Speaking, Q is 2\pi times the ratio of the total energy stored divided by the energy lost in a single cycle or equivalently the ratio of the stored energy to the energy dissipated over one radian of the oscillation.[9]

It is a dimensionless parameter that compares the time constant for decay of an oscillating physical system's amplitude to its oscillation period. Equivalently, it compares the frequency at which a system oscillates to the rate at which it dissipates its energy.

Equivalently (for large values of Q), the Q factor is approximately the number of oscillations required for a freely oscillating system's energy to fall off to 1/e^{2\pi}, or about 1/535 or 0.2%, of its original energy.[10]

The width (bandwidth) of the resonance is given by

\Delta f = \frac{f_0}{Q} \, ,

where f_0 is the resonant frequency, and \Delta f, the bandwidth, is the width of the range of frequencies for which the energy is at least half its peak value.

The factors Q, damping ratio ζ, and attenuation α are related such that[11]

\zeta = \frac{1}{2 Q} = { \alpha \over \omega_0 }.

So the quality factor can be expressed as

Q = \frac{1}{2 \zeta} = { \omega_0 \over 2 \alpha },

and the exponential attenuation rate can be expressed as

\alpha = \zeta \omega_0 = { \omega_0 \over 2 Q }.

For any 2nd order low-pass filter, the response function of the filter is[11]

H(s) = \frac{ \omega_0^2 }{ s^2 + \underbrace{ \frac{ \omega_0 }{Q} }_{2 \zeta \omega_0 = 2 \alpha }s + \omega_0^2 } \,

For this system, when Q > 0.5 (i.e., when the system is underdamped), it has two complex conjugate poles that each have a real part of \alpha. That is, the attenuation parameter \alpha represents the rate of exponential decay of the oscillations (e.g., after an impulse) of the system. A higher quality factor implies a lower attenuation, and so high Q systems oscillate for long times. For example, high quality bells have an approximately pure sinusoidal tone for a long time after being struck by a hammer.
 
In simple terms, Q is height of a peak divided by the width of the peak measured halfway up the peak.

(Man, that wiki is too complex, whoever wrote that has no life!!)
 
I don't even mess with "Q". I just say "wide" or "narrow" cut/boost.
 
Physically Speaking, Q is 2\pi times the ratio of the total energy stored divided by the energy lost in a single cycle or equivalently the ratio of the stored energy to the energy dissipated over one radian of the oscillation.[9]

It is a dimensionless parameter that compares the time constant for decay of an oscillating physical system's amplitude to its oscillation period. Equivalently, it compares the frequency at which a system oscillates to the rate at which it dissipates its energy.

Equivalently (for large values of Q), the Q factor is approximately the number of oscillations required for a freely oscillating system's energy to fall off to 1/e^{2\pi}, or about 1/535 or 0.2%, of its original energy.[10]

The width (bandwidth) of the resonance is given by

\Delta f = \frac{f_0}{Q} \, ,

where f_0 is the resonant frequency, and \Delta f, the bandwidth, is the width of the range of frequencies for which the energy is at least half its peak value.

The factors Q, damping ratio ζ, and attenuation α are related such that[11]

\zeta = \frac{1}{2 Q} = { \alpha \over \omega_0 }.

So the quality factor can be expressed as

Q = \frac{1}{2 \zeta} = { \omega_0 \over 2 \alpha },

and the exponential attenuation rate can be expressed as

\alpha = \zeta \omega_0 = { \omega_0 \over 2 Q }.

For any 2nd order low-pass filter, the response function of the filter is[11]

H(s) = \frac{ \omega_0^2 }{ s^2 + \underbrace{ \frac{ \omega_0 }{Q} }_{2 \zeta \omega_0 = 2 \alpha }s + \omega_0^2 } \,

For this system, when Q > 0.5 (i.e., when the system is underdamped), it has two complex conjugate poles that each have a real part of \alpha. That is, the attenuation parameter \alpha represents the rate of exponential decay of the oscillations (e.g., after an impulse) of the system. A higher quality factor implies a lower attenuation, and so high Q systems oscillate for long times. For example, high quality bells have an approximately pure sinusoidal tone for a long time after being struck by a hammer.
'Kinnell man !!

In simple terms, Q is height of a peak divided by the width of the peak measured halfway up the peak.
Simple terms ? :D You're talking to a maths O level failure here. 2+2 = 4 ~ those are simple terms !
 
Back
Top