You almost got it, just think it through.
There are 8 bits in a byte, so dividing the bit depth by 8 gives you the same depth in bytes. Then each sample is equal in size to the bit depth, and you have a fixed number of samples per second.
So
24/96:
3 * 96,000 = 288,000 bytes per second
24/48:
3 * 48,000 = 144,000 bytes per second
24/44.1:
3 * 44,100 = 132,300 bytes per second
16/48:
2 * 48,000 = 96,000 bytes per second
16/44.1:
2 * 44,100 = 88,200 bytes per second
So if you want to calculate the total number of bytes required by a track, you multiply the appropriate figure above by the number of channels in a track (1 or 2) and the length of the track in seconds.
A 90 second 24/44.1 stereo track thus takes:
90 * 2 * 132,300 = 23,760,000 bytes, or 23.76MB
(note that windows actually defines a megabyte as 1024KB, which is 1,048,576 bytes so the 23.76MB figure above may appear as 22.66MB in the windows file browser. this doesn't change the number of bytes contained in the file, just its representation)
Slackmaster 2000
