No, taper and loading are very different. Let's consider just one pickup, say it's a 10K humbucker with a 500K log taper pot, no tone control, 1M load at the amp, treat all impedances as pure resistive and ignore stray capacitance. In other words, complete make-believe
A typical audio taper pot is something like 16% resistance at 50% rotation. So our 500K pot will split 420K/80K.
Standard wiring has the full pot resistance as the load on the pickup, and the amp connected to wiper. What is the net load on the pickup?
420K + (80K || 1M) = 494K
What about the signal drop across the pot? That is:
20 * log (74K / 494K) = -16.5dB
And what about output impedance? That is:
(10K + 420K) || 80K = 67K
The same figures for alternate wiring:
load on pickup:
(420K + 1M) || 80K = 76K
output impedance:
420K + (10K || 80K) = 429K
signal loss--this is more complicated, effectively you have a loss from the load on the pickup plus the loss due to output impedance, here is a simple version:
20 * log ( (10K / 90K) * (420K || 1M) ) = -4dB
It gets more complicated with the middle position since you have to consider the effects of the second 500K load.
But in conclusion, you can see that the widely varying pickup load and output impedance of the alternate wiring will yield substantially varying results once we consider the inductive source impedance of the pickup and the cable's capacitance. The result will be to shed highs much more rapidly than standard wiring. I imagine many people using alternate wiring resort to treble shunt or bypass caps to compensate.
I personally enjoy the treble response of a relatively unloaded, underwound (5K) humbucker. I can always roll off highs using a tone control (at the guitar or amp) if I want a different tone. In contrast, trying to recover HF response from a guitar wired to shed highs will usually yield poor signal to noise as a result.
Most of all, it's nice to have a volume control that acts solely like a volume control and a tone control that does the same. That is a difficult goal with passive wiring . . . I think the answer is a transformer, but not too many people see things my way.