yetipur said:
to southside glen,
ok i understand that stereo reverb is a reflection from the surrounding enviornment. But why then would there be left and right ins and outs? Is this to cover the whole Panning spectrum? If the reverb is always in the middle so to speak, why would anyone want to do it this way?
A stereo image is not necessarily "always in the middle", it's a stereo image that could have it's energy distributed anywhere within the panning spectrum. But regardless of how that energy is spread between the left and right speakers, the image remains stereo, and cann't be "panned".
In the case of stereo reverb, picture it this way. You're standing in an empty hall. There is a guitarist a few feet in front of you, standing in center, midway between the left and right walls. The reverb comes back not from the guitar, but from the floor, walls and ceiling. It comes back from the hall. Now move the guitarist halfway towards the left wall. This is basically the same as panning the guitar track 50% left. Does the reverb "move"? No, the "location" of the reverb remains the same because the location of the floor, walls and ceiling remain the same. The *character*, the sound and the energy distribution of the reverb changes when the guitar moves within the room, but the location of the hall itself - and therefore the stereo image - remains static.
Now, the movement of the guitar within the room is the reason for the L&R inputs on the reverb. In order to tell the reverb that the guitar is halfway between the center and the left wall, that pan information must be sent o the reverb. If we just send it a mono track (like a mono send from the mixer), there is no pan information; it's just a mono track. We need to send it a stereo feed that has the guitar panned 50% to the left channel for the reverb to "know" that it's dealing with a panned signal. Note, though, that the reverb will still return a standard stereo image through it's L&R outputs/returns. It's just that the image it creates will be a simulation of the entire stationary hall, a simulation of what that entire hall reverb would sound like with a guitar located inside it halfway to the left wall.
If you want to localize the sound of a reverb, as if the reverb were coming out of the guitar amp instead of from the surrounding hall itself, then the most accurate simulation of that would be to return a mono reverb on a stereo return (i.e. a L&R return with equal and identical signal on both channels). Then you can use the pan on the return to "move" the reverb sound where you want. Which brings us to...
yetipur said:
what is the point of having an AUX pan knob like I do on AUX2?????
I explain that above, and mixsit also gives some alternate reasoning. The thing is, when you're receiving true stereo information - where the information on the L&R returns is not necessarily identical (it's not a mono signal) - like you are from a stereo reverb, there really is no "panning" in the traditional sense. Assuming you are actually returning both L&R back to the mixer from the Lexicon (you are using both channels, right?), you should be able to use the pan control on the return (it *is* on the return, right?) to adjust relative volume between the stereo L&R channels - much like a balance control on a home stereo amplifier, but like with the balance conrtol, the "pan image" may not appear as moving a point source sound through the degrees as you expect, instead just as a shifting of volume balance.
G.