6 ohm cab + 8 ohm cab run Par' = ? 3.5 ohm load?

Freudian Slip

New member
3.5 just seems to simple and easy so I thought I'd ask.
If I run a 6 ohm speaker and a 8 ohm speaker parallel what would that make the ohm load?

Anyone?

I need a refresher.

Thanks

F.S.
 
Close enough

I get 3.43 ohms, which I suppose rounds off to 3.5.

(R1 * R2) / (R1 + R2)

(6 * 8) / (6 + 8) = 3.43. I think.

You can actually derive the general rule from just knowing that I = E/R.

Itotal = I1 + I2
I1 = E / R1
I2 = E / R2
Itotal = E/R1 + E/R2 = E (1/R1 + 1/R2) = E (R1 + R2)/(R1 * R2)
= E / (R1 * R2) / (R1 + R2)

Since, by definition, you know that Itotal = E / Rtotal, it follows that:

Rtotal = (R1 * R2) / (R1 + R2)
 
Thanks sjjohnston.

I knew that two speakers of equal resistance ran parralell cutt the resistance in half but was just guessing as to what two unequal speakers would do.


F.S.
 
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